0.014809-0.042x=3x^2

Solution for 0.014809-0.042x=3x^2 equation:

0.014809-0.042x=3x^2

We move all terms to the left:

0.014809-0.042x-(3x^2)=0

determiningTheFunctionDomain
-3x^2-0.042x+0.014809=0

a = -3; b = -0.042; c = +0.014809;
Δ = b2-4ac
Δ = -0.0422-4·(-3)·0.014809
Δ = 0.179472
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.042)-\sqrt{0.179472}}{2*-3}=\frac{0.042-\sqrt{0.179472}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.042)+\sqrt{0.179472}}{2*-3}=\frac{0.042+\sqrt{0.179472}}{-6}
$